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Subj:.....9-Digit Pandigital (S666)
          By Dave Ellis
          From: Anonymous Jr. on 10/10/2009
Drawing from Valdosta State University...

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Source: http://www.puzzlet.co.uk/Puzzlets/Puzzlet_002.html

A pandigital is an integer containing every digit.  In this
particular case, we're dealing with the 9-digit pandigital,
since the zero isn't used.

Take all the digits 1 through 9 in order, and insert as
many plus and minus signs as you wish, wherever you want,
to make an arithmetic sum of 100.  For example,

    123 + 45 - 67 + 8 - 9 = 100

Are there any more ways of punctuating a 9-digit pandigital
with plus and minus signs to make a sum of 100 as in the
example above?  If so, what are they?

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Finger pointing down
from darrell94590 on 1/2/2006
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Drawing from Ripleys-Believe It Or Not
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              THE SOLUTION
 

 Mr. Ellis wrote a basic program which can be seen at
 http://www.puzzlet.co.uk/Solutions/Puzzlet_002_sol.html
 which generated these twelve solutions.

 123-45-67+89 = 100
 123+45-67+8-9 = 100
 123+4-5+67-89 = 100
 123-4-5-6-7+8-9 = 100
 12+3-4+5+67+8+9 = 100
 12-3-4+5-6+7+89 = 100
 12+3+4+5-6-7+89 = 100
 1+23-4+56+7+8+9 = 100
 1+23-4+5+6+78-9 = 100
 1+2+34-5+67-8+9 = 100
-1+2-3+4+5+6+78+9 = 100
 1+2+3-4+5+6+78+9 = 100

From: lubin100 on 10/25/2009 
 Dick added the following solutions:

 98+7+6-5-4-3+2-1 = 100
 98+7-6+5-4+3-2-1 = 100
 98-7+6+5+4-3-2-1 = 100
 98-7+6-5+4+3+2-1 = 100
 98-7+6+5-4+3-2+1 = 100
 98+7-6+5-4-3+2+1 = 100
 98-7-6+5+4+3+2+1 = 100
 9+8+76+5+4-3+2-1 = 100
 9+8+76+5-4+3+2+1 = 100

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